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Đội hình Inhulets vs FK Zorya Luhansk, 08/11/2022
Đội hình ra sân
Inhulets HLV: Lavrynenko S.
4-2-3-1
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12. Palamarchuk O. (G)
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44. Sakiv T.
-
55. Kovalyov M.
-
28. Pavlov V. (C)
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33. Nagiyev D.
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8. Klymenko V.
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88. Kukharuk A.
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29. Smolyakov A.
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5. Zaporozhets E.
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10. Kozak O.
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9. Marusych M.
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31. Rusyn N.
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9. Myshnyov D.
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10. Buletsa S.
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20. Churko V.
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70. Kyryukhantsev I.
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5. Brazhko V.
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77. Danchenko O.
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44. Batagov A.
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32. Imerekov M. (C)
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2. Butko B.
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53. Matsapura D. (G)
FK Zorya Luhansk HLV: van Leeuwen P.
4-1-4-1
Dự bị
7

Bliznichenko A.
21

Chenbay S.
24

Golovkin I.
15

Korobenko A.
14

Kravchuk D.
13

Kucher D. (G)
23

Kucherenko O.
19

Odaryuk V.
60

Pospelov D.
97

Rezepov D.
26

Sydorenko V.
91

Alefirenko D.
19

Alibekov A.
7

Antyukh D.
14

Khlan M.
8

Lunyov M.
21

Mykhaylenko M.
17

Nagnoynyi D.
1

Saputin O. (G)
28

Skakhov Y.
74

Snurnitsyn I.
30

Turbayevskyi M. (G)
47

Vantukh R.
Huấn luyện viên

Lavrynenko S.

van Leeuwen P.